Try this beautiful problem from AMC 10A, 2018 based on **Number theory**.

## Problem – Number Theory

Let’s try this problem number 10 from AMC 10A, 2018 based on Number Theory.

Suppose that the real number $x$ satisfies $\sqrt {49-x^2}$ – $\sqrt {25-x^2}$ = $3$.

What is the value of $\sqrt {49-x^2}$ + $\sqrt {25-x^2}$?

- 8
- $\sqrt 33 + 8$
- 9
- $2\sqrt10+4$
- 12

**Key Concepts**

**Number Theory**

**Real number**

**Square root**

## Check the Answer

Answer: 8

AMC 10 A – 2018 – Problem No.10

Mathematics can be fun by Perelman

## Try with Hints

As a first hint we can start from here :

In order to get rid of the square roots, we multiply by the conjugate. Its value is the solution.The \(x^2\) terms cancel out.

\((\sqrt {49 – x^2} +\sqrt {25 – x^2}) (\sqrt {49 – x^2}) -(\sqrt {25 – x^2})\)

= 49 -\(x^2 – 25 + x^2\)

=24

Given that \(\sqrt {49 – x^2}) -(\sqrt {25 – x^2})\) = 3

\(\sqrt {49 – x^2} +\sqrt {25 – x^2}\) = \(\frac {24}{3}\)

= 8

## Other useful links

- https://www.cheenta.com/side-of-triangle-2011-amc-10b-problem-9/
- https://www.youtube.com/watch?v=04jcZuI4JKc&t=3s